juniper8 Posted August 5, 2010 Share Posted August 5, 2010 Hello, I am Building some new speaker cabinets out of 3/4 Baltic Birch and have decided that around 9ft3 internal volumn would suit my needs. if the base had to be 30 inches wide and 19 inches in depth how high would the speaker have to be to reach the 9ft3 number? Thanks any input would be great ! Quote Link to comment Share on other sites More sharing options...
CECAA850 Posted August 5, 2010 Share Posted August 5, 2010 I would think around 27 or 28" tall, but I didn't subtract the thickness of the plywood. You'd need to know if the sides would be mounted on the top of the base or the sides of the base to get an exact height. Quote Link to comment Share on other sites More sharing options...
Guest " " Posted August 5, 2010 Share Posted August 5, 2010 33.8 inches here's a nice on line calculator http://www.hometheatershack.com/forums/enclosure-volume-calculator/ Quote Link to comment Share on other sites More sharing options...
jason str Posted August 5, 2010 Share Posted August 5, 2010 This makes things easy as pie. http://www.the12volt.com/caraudio/boxcalcs.asp#rec Quote Link to comment Share on other sites More sharing options...
CECAA850 Posted August 5, 2010 Share Posted August 5, 2010 33.8X30X19=19266 cu in divided by 1728 (cu in per cu ft) = 11.15 cu ft. The wood must displace over 2 cu ft. Guess so. Quote Link to comment Share on other sites More sharing options...
CECAA850 Posted August 5, 2010 Share Posted August 5, 2010 33.8 inches here's a nice on line calculator http://www.hometheatershack.com/forums/enclosure-volume-calculator/ That's nice, it takes driver displacement into consideration. Quote Link to comment Share on other sites More sharing options...
juniper8 Posted August 5, 2010 Author Share Posted August 5, 2010 Thanks for the responses and links and making it so easy! Quote Link to comment Share on other sites More sharing options...
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