Dave A Posted March 6, 2020 Share Posted March 6, 2020 On these crossovers I would like to know if there is any reason to leave the components being jumped over on the circuit board. It just seems to me with my lack of real understanding about electronics that if I am going to jump over a coil but still leave it in the circuit I am not really entirely removing the coils influence on the circuit. Would it not be better to just remove the various items being bypassed? Quote Link to comment Share on other sites More sharing options...
Marvel Posted March 6, 2020 Share Posted March 6, 2020 The component will electrically be removed by putting the jumper in place. the entire signal will go through the jumper. Quote Link to comment Share on other sites More sharing options...
Dave A Posted March 6, 2020 Author Share Posted March 6, 2020 OK explain to me how electricity knows to avoid something that is still there? Quote Link to comment Share on other sites More sharing options...
Marvel Posted March 6, 2020 Share Posted March 6, 2020 It is a path of least resistance (the wire). Use your meter on each side of the components, and then put the jumper on and measure. Should be zero ohms with the jumper. It's easier to leave the extra parts on there, even if it looks a little messy. Quote Link to comment Share on other sites More sharing options...
glens Posted March 6, 2020 Share Posted March 6, 2020 There will still be the potential across the component, and possibly even a minute amount of current flow through it, but it's influence will be so negligible that it's not worth the effort to remove it entirely. I'd be surprised if even Mr. Medwin could detect its presence! 1 Quote Link to comment Share on other sites More sharing options...
Dave A Posted March 6, 2020 Author Share Posted March 6, 2020 1 hour ago, glens said: There will still be the potential across the component, and possibly even a minute amount of current flow through it, but it's influence will be so negligible that it's not worth the effort to remove it entirely. I'd be surprised if even Mr. Medwin could detect its presence! yeah but I can't fit 8g jumper wire under the board. 1 Quote Link to comment Share on other sites More sharing options...
rigma Posted March 7, 2020 Share Posted March 7, 2020 On 3/5/2020 at 11:00 PM, Dave A said: yeah but I can't fit 8g jumper wire under the board. Now that's funny😵 Quote Link to comment Share on other sites More sharing options...
ClaudeJ1 Posted March 8, 2020 Share Posted March 8, 2020 On 3/5/2020 at 9:13 PM, Marvel said: It is a path of least resistance (the wire). Use your meter on each side of the components, and then put the jumper on and measure. Should be zero ohms with the jumper. It's easier to leave the extra parts on there, even if it looks a little messy. It should end up at NEAR Zero ohms, since many meters typically include the resistance of the Meter's Wires, that need to be subtracted from the reading. YMMV. Quote Link to comment Share on other sites More sharing options...
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